A 5 kg object is launched from a 35 m high cliff at an angle of 30 degrees with a speed of 100 m/s. How far from the cliff does it hit the ground

The object will hit the ground at 882.77 m from the lunch

Explanation:

we are to find the range of the motion

What is range?

It is the distance from the point of projection to the point where the object hits the ground

R=(v^2sin2θ)/g

Given data

v= 100 m/s

θ= 30 degree

g= 9.81 m/s^2

Substituting to find the R we have

R= 100^2 *sin(2*30)/9.81

R= (10000*0.866)9.81

R= 8660/9.81

R= 882.77 m

d. air pressure decreases as altitude increases.

hi,

what occurs during a solar eclipse?

there are small tides across earth.

the moon is between earth and the sun.

p.s. im not sure if the first answer is correct because during a solar ecliphse there are spring tides and i dont know if they are the same.