A cylindrical can of radius R is rolling across a horizontal surface without slipping. A. After one complete revolution of the can, what is the distance that its center of mass has moved.
B. Would this distance be greater or smaller if slipping occurred?

a) 2πR

b) greater

Explanation:

Radius of the cylinder = R

a) after one complete revolution, the center of mass would have moved a distance equal to the circumference of the radius formed by the cylinder.

distance moved = 2πR

b) If slipping occurred, there will be some distance lost during rotation, which will increase the distance that the center of mass will have to move.

what do the notation's look like?

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.