I WILL GIVE BRAINLIEST!! :) The value of the total current is: A. 3.5A B. 4.0 A C. 4.5A D. 5.0 A

Option C. 4.5 A

Explanation:

We'll begin by calculating the equivalent resistance of R1 and R3. This can be obtained as follow:

R1 = 6 Ω

R3 = 3 Ω

Equivalent of R1 and R3 =?

Since R1 and R3 are in parallel connections, we shall their equivalence as follow:

Equivalent of R1 and R3 = (R1×R3) /(R1 + R3)

Equivalent of R1 and R3 = (6×3)/(6+3)

Equivalent of R1 and R3 = 18/9

Equivalent of R1 and R3 = 2 Ω

Next, we shall determine the equivalent resistance in the circuit.

This is illustrated below:

R2 = 2 Ω

Equivalent of R1 and R3 = 2 Ω

Equivalent resistance (R) in the circuit =?

Note: Equivalent of R1 and R3 is in series connection with R2.

Equivalent Resistance (R) = (Equivalent of R1 and R3) + R2

Equivalent Resistance (R) = 2 + 2

Equivalent Resistance (R) = 4 Ω

Finally, we shall determine the total current in the circuit as follow:

Potential difference (V) = 18 V

Equivalent Resistance (R) = 4 Ω

Current (I) =.?

From ohm's:

V = IR

Where V is the potential difference.

I is the current.

R is the resistance.

V = IR

18 = I × 4

Divide both side by 4

I = 18/4

I = 4.5 A

Therefore, the total current in the circuit is 4.5 A.

the electric field is a “force field” around a charged object that illustrates the direction the electric force would push an imaginary