A hockey puck moves 26 meters northward, then 12 meters southward, and finally 6 meters northward what is the distance and the displacement? PLEASE HELP MEEE

The displacement is 20 m northward.

The distance is 44 m

Explanation:

Let northward motion be in positive direction

Let southward motion be in negative direction

Dispalcement is the shortest path covered by the hockey puck at a specified direction.

The dispalcement of the hockey puck will be calculated as;

Displacement = 26 m northward - 12m southward + 6 m northward

Displacement =  20 m in northward direction

Distance is the total path covered by the hockey puck.

Distance = 26 m + 12m + 6 m

Distance = 44 m

50 inches should be the resultant vector

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow