A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the smaller piston to obtain a force of 1600 N at the larger piston

The force that should be applied to the smaller piston is 400 N.

Given that,

Based on the above information, the calculation is as follows:

F = 400 N

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400 N

Explanation:

Pressure is equal on both pistons.

P = P

F / A = F / A

F / (πd²/4) = F / (πd²/4)

F / d² = F / d²

1600 N / (8.0 cm)² = F / (4.0 cm)²

F = 400 N

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