How wide is the central diffraction peak on a screen 2.30 m behind a 0.0368-mm-wide slit illuminated by 558-nm light

The  value

Explanation:

From the question we are told that

   The  distance of the screen is  

   The  width of the slit is  

   The  wavelength is  

The  width of the central diffraction peak is  mathematically represented as

Where  y is the distance from the center to the high peak which  is mathematically represented as

substituting values

we need to know the time interval during which the force acts. impulse of force = momentum change