Firecracker A is 300 m from you. Firecracker B is 600 m from you in the same direction. You see both explode at the same time. Define event 1 to be "firecracker A explodes" and event 2 to be "firecracker B explodes." Does. event 1 occur before, after, or at the same time as event 2? Explain.

e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

Explanation:

This is an ejercise in special relativity, where the speed of light is constant.

Let's carefully analyze the approach, we see the two events at the same time.

The closest event time is

       c = (x₁-300) / t

       t = (x₁-300) / c

The time for the other event is

       t = (x₂- 600) / c

since they tell us that we see the events simultaneously, we can equalize

        (x₁ -300) / c = (x₂ -600) / c

         x₁ = x₂ - 300

We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )

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