If you wish to detect details of the size of atoms (about 1 ✕ 10−10 m) with electromagnetic radiation, it must have a wavelength of about this size. (a) What is its frequency?
(b) What type of electromagnetic radiation might this be?

(a) The frequency of the electromagnetic radiation is

(b)  The electromagnetic radiation is ultra violet ray.

The given parameters;

The frequency of the electromagnetic radiation is calculated as follows;

The frequency range of ultra violet ray is between 10¹⁴ to 10¹⁸ m.

Thus, the electromagnetic radiation is ultra violet ray.

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a) 3×10^18 Hz

b) The electromagnetic wave is an x-ray

Explanation:

We know that the speed of an electromagnetic wave is given by;

c= λf

Where;

c= speed of electromagnetic waves = 3×10^8 ms-1

f= frequency of electromagnetic waves= the unknown

λ = wavelength of the electromagnetic wave= 1 ×10^-10 m

Hence;

f = c/λ= 3×10^8/ 1×10^-10

f= 3×10^18 Hz

b) The electromagnetic wave is an x-ray.

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .