A resistor is connected across an oscillating emf. The peak current through the resistor is 2.0 A. What is the peak current if: a. The resistance R is doubled?
b. The peak emf εo is doubled?
c. The frequency ω is doubled?

(a) When the resistance R is doubled, I = 1 A

(b) When the peak emf εo is doubled, I = 4 A

(c)  When the frequency ω is doubled, I = 2 A

Explanation:

Given;

peak current through the resistor, I = 2.0 A

According to ohms law the peak current through the circuit is given by;

(a) When the resistance R is doubled;

(b)When the peak emf εo is doubled

(c) When the frequency ω is doubled

Peak current through resistor is independent of frequency

I₂ = 2.0 A