A vehicle moving with a uniform a acceleration of 2m/s and has a velocity of 4m/s at a certain time . what is will its velocity be
a: 1s later
b: 5s later.

1 second later the vehicle's velocity will be:

5 seconds later the vehicle's velocity will be:

Explanation:

Recall the formula for the velocity of an object under constant accelerated motion (with acceleration ""):

Therefore, in this case  and

so we can estimate the velocity of the vehicle at different times just by replacing the requested "t" in the expression:

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂