A 5.0 V battery storing 43.0 kJ of energy supplies 1.5 A of current to a circuit. How much energy does the battery have left after powering the circuit for 1.0 h? A. 43 kJ B. 16 kJ C. 41 kJ D. 27 kJ

B. 16 kJ

Explanation:

Energy = VIt Equation 1

Where V = Voltage, I = Current, t = time

Given: V = 5.0 V, I = 1.5 A, t = 1 h = 3600 s.

Substitute these values into equation 2

E = 5.0(1.5)(3600)

E = 27000 J

E = 27 kJ.

Amount of energy left = 43 kJ - 27 kJ

Amount of energy left = 16 kJ.

Hence the right option is B. 16 kJ

work: w = fd (given)

work done by chet   =50*1 = 50 j

work done by mika =40*2 = 80 j

work done by sara =30*1.5 = 45 j

work done by bill =60*0.5 = 30 j

students in order from the greatest amount of work done to the least is mika> chet> sara> bill

hence option (b) is correct.