At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 7.45 ✕ 106 m/s perpendicular to the Earth's magnetic field at an altitude where the field strength is 1.10 ✕ 10−5 T

The speed of the proton is 4059.39 m/s

Explanation:

The centripetal force on the particle is given by;

The magnetic force on the particle is given by;

The centripetal force on the particle must equal the magnetic force on the particle, for the particle to remain in the circular path.

where;

r is the radius of the circular path moved by both electron and proton;

⇒For electron;

⇒For proton

The speed of the proton is given by;

Therefore, the speed of the proton is 4059.39 m/s

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explanation: