Light with an intensity of 1 kW/m2 falls normally on a surface and is completely absorbed. The radiation pressure is

The radiation pressure of the light is 3.33 x 10⁻⁶ Pa.

Explanation:

Given;

intensity of light, I = 1 kW/m²

The radiation pressure of light is given as;

I kW = 1000 J/s

The energy flux density = 1000 J/m².s

The speed of light = 3 x 10⁸ m/s

Thus, the radiation pressure of the light is calculated as;

Therefore, the radiation pressure of the light is 3.33 x 10⁻⁶ Pa.

the force on the thing and the distance the force moves the thing