A 2-slit arrangement with 60.3 μm separation between the slits is illuminated with 482.0 nm light. Assuming that a viewing screen is located 2.14 m from the slits, find the distance from the first dark fringe on one side of the central maximum to the second dark fringe on the other side. A. 24.1 mm B. 34.2 mm C. 68.4 mm D. 51.3 mm

The distance is  

Explanation:

From the question we are told that

   The distance of separation is  

   The wavelength is  

    The distance of the screen is

Generally the distance of a fringe from the central maxima is mathematically represented as

For the first dark fringe m = 0

For the second dark fringe m = 1

So the distance from the first dark fringe on one side of the central maximum to the second dark fringe on the other side is

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.