A balloon contains 1.21 x 105 L of ideal gas at 265K. The gas is then cooled to 201 K. What is the volume (L) assuming no gas enters or exits the balloon

The new volume will be 0.918 x 10^5 L

Explanation:

initial volume   = 1.21 x 10^5 L

Initial temperature = 265 K

Final volume = ?

Final temperature = 201 K

Th gas is an ideal gas.

For ideal gases, the equation / = / = constant

substituting value, we have

(1.21 x 10^5)/265 = /201

=  24321000/265 = 91777.4 L

= 0.918 x 10^5 L

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