The four wheels of a car are connected to the car's body by spring assemblies that let the wheels move up and down over bumps and dips in the road. When a 68 kg (about 150 lb) person sits on the left front fender of a small car, this corner of the car dips by about 1.2 cm (about 1/2 in). If we treat the spring assembly as a single spring, what is the approximate spring constant?

k=

The approximate  spring constant is  

Explanation:

From the question we are told that

   The  mass of the person is  

     The  dip of the car is  

Generally according to hooks law  

here the force F is the weight of the person which is mathematically represented as

=>    

=>    

=>    

=>  

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

e) none of the above answers are correct