What is the electric force acting between two charges of 0.0072 C and -0.0060 C that are 0.0040 m apart?

Fe = 2.4 × 10^10 N

Explanation:

Given the following :

q1 = charge 1 = 0.0072 C = positive direction

q2 = charge 2 = 0.0060 C = - ve direction

r = distance = 0.0040

Using the relation :

Fe = K(q1q2) /r^2

Where K = columb's constant = 9×10^9 Nm^2/C^2

Fe = electric force

Fe = 9×10^9(0.0072 * 0.0060) / 0.0040^2

Fe = [9×10^9 (0.0000432)] / 0.000016

Fe = 388,800 / 0.000016

Fe = 24300000000

Fe = 2.43 × 10^10 N

car a and b are moving in opposite directions

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answer: electrons