Physics, 12.08.2020 05:01 emilyblaxton

You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that emerges from this polarizer falls on a second ideal polarizer. The light that emerges from the second polarizer has intensity 15.0 W/m2. Find the intensity of the light that emerges from the first polarizer.

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Answer from: milkshakegrande101

The intensity of light from the first polarizer is I_1 = 26 W/m^2

Explanation:

The intensity of the unpolarized light is $I_o = 52.0 \ W/m^2$

Generally the intensity of light that emerges from the first polarized light is

$I_1 = \frac{I_o}{2 }$

substituting values

$I_1 = \frac{52. 0}{2 }$

I_1 = 26 W/m^2

Answer from: Quest

electromagnetic shielding is the practice of reducing the electromagnetic field in a space by blocking the field with barriers made of conductive or magnetic materials. shielding is typically applied to enclosures to isolate electrical devices from their surroundings, and to cables to isolate wires from the environment through which the cable runs. electromagnetic shielding that blocks radio frequency electromagnetic radiation is also known as rf shielding.

the shielding can reduce the coupling of radio waves, electromagnetic fields and electrostatic fields. a conductive enclosure used to block electrostatic fields is also known as a faraday cage. the amount of reduction depends very much upon the material used, its thickness, the size of the shielded volume and the frequency of the fields of interest and the size, shape and orientation of apertures in a shield to an incident electromagnetic

from wikipedia

Answer from: Quest

from wikipedia

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You shine unpolarized light with intensity 52.0 W/m2 on an ideal polarizer, and then the light that...

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