a bird statue with a mass 0.2 kg hangs from a rubber band with spring constant 30 N/m. How much is the rubber band stretched when the statue hangs motionless

Distance : 0.06533 meters or 65.33 mm

Explanation:

To solve this problem we can make the forces equal when the system is at equilibrium.

mass gravity ( constant ) = spring constant

where l = the length at which the rubber band is stretched

0.2 kg 9.8 m / s² = 30 N/m

1.96 kg m / s² = 30 N/m

l = 1.96 kg m / s² / 30 N/m = 0.06533 meters / 65.33 mm

The rubber band is stretched a distance of 0.06533 meters, or 65.33 mm.