A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the a. Stress of the wire.
b. Strain of the wire

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m =

Extended by = 0.25mm =

Based on the above information, the calculation is as follows

a. The Stress of the wire is

here area of circle = perpendicular to the are i.e cross-sectional  i.e

=

=

Now place these above values to the above formula

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

=

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.