Active 13 minutes ago 6. Thrust exerted by an object of area 20 m experiencing pressure 150 Nm‐² is
a 3000 km
b. 3000 N
c. 2800 Kg
d 2800 N/m

3000 N

Explanation:

As we know that

pressure=force/area

force=thrust

so pressure=thrust/area

thrust=pressure*area

pressure=150 Nm^-2

area=20m^2

so thrsut=150*20=3000 N

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be

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