A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?

Explanation:

Resultant of 12 and 3 ohm in series = 15 ohm

Resultant of 6 and 3 ohm = 9 ohm

Total resultant resistance of circuit = 15 x 9 / (15 + 9)

= 5.625 ohm

current drawn from battery = 4 / 5.625

= .711 A

ii )current through 12 ohm = 4 / (12 + 3 )   , because potential  diff over 12 and 6 ohm will be 4 V .

current through 12 ohm = .267 A

iii )

current through 6 ohm

= .711 - .267

= .444 A

potential difference

= .444 x 6

= 2.664 V .

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this