The distance measured between five successive crests of a wave motion executed by a photon of an electromagnetic radiation is 2.4cm. 1. Determine the wavelength in micrometers
2. what is the frequency of the photon
3. what is the energy possessed by the photon.

1. λ = 0.48 cm = 4800 μm

2. υ = 6.25 x 10¹⁰ Hz

3. E = 4.14 x 10⁻²³ J

Explanation:

1.

Since, the wavelength is defined as the distance between two consecutive or successive crests or troughs. Therefore, in this case the wavelength will be equal to:

Wavelength = λ = Distance between 5 successive crests/5

λ = 2.4 cm/5

λ = 0.48 cm = 4800 μm

2.

The frequency of photon can be given as:

υ = c/λ

where,

υ = frequency of photon = ?

c = speed of light = 3 x 10⁸ m/s

λ = wavelength = 0.48 cm = 0.0048 m

Therefore,

υ = (3 x 10⁸ m/s)/(0.0048 m)

υ = 6.25 x 10¹⁰ Hz

3.

Now, the energy of photon is given as:

E = hυ

where,

E = Energy = ?

h = Plank's Constant = 6.626 x 10⁻³⁴ J.s

Therefore,

E = (6.626 x 10⁻³⁴ J.s)(6.25 x 10¹⁰ Hz)

E = 4.14 x 10⁻²³ J

the duration of a photographic flash is related to an rc time constant, which is 0.100 μs for a certain camera.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m