A ball is thrown horizontally from the top of a building 54 m high. The ball strikes the ground at a point 35 m horizontally away from and below the point of release. What is the speed of the ball just before it strikes the ground

V=34.2 m/s

Explanation:

Given that

Height , h= 54 m

Horizontal distance , x = 35 m

Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.

In vertical direction :

We know that

Now by putting the values in the above equation we got

Assume

Thus

We also know that

In horizontal direction :

Thus the resultant velocity

V=34.2 m/s

Therefore the velocity will be 34.2 m/s.

come closer and become far apart and become steam/gas

grav force prop 1/r squared 2r all squared is 4rsquared 1/4rsquared quartered