What would the Hall voltage be if a 2.00-T field is applied across a 10-gauge copper wire (2.588 mm in diameter) carrying a 20.0-A current

The hall  voltage is

Explanation:

From the question we are told that

     The magnetic field is  

     The diameter is  

       The  current is  

The radius can be evaluated as

substituting values

The hall voltage is mathematically represented as

where is the  drift velocity of the electrons on the current carrying conductor which  is mathematically evaluated as

Where n is the number of electron per cubic meter which for copper is  

  A is the cross - area of the wire  which is mathematically represented as

substituting values

so the drift velocity is  

Thus the hall voltage is

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graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat