Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0 X 1012 electrons are added to sphere A, then the two spheres are separated. Afterward, what is the charge of sphere A

Charge that will be left on sphere A is -8 x 10^-8 C

Explanation:

Number of electrons = 1.0 x 10^12 electrons

charge on an electron is = -1.6 × 10^-19 coulombs

for the number of electron, total charge = (1.0 x 10^12) x (-1.6 × 10^-19)

==> -1.6 x 10^-7 C

Since the two spheres were in contact when the charge was added to one of the spheres A, the sphere will then be distributed between the two spheres A and B equally. This means that after separation, sphere A will be left with

==> (-1.6 x 10^-7 C) ÷ 2 = -8 x 10^-8 C

the bal will not change its velocity.