It takes 144 J of work to move 1.9 C of charge from the negative plate to the positive plate of a parallel plate capacitor. What voltage difference exists between the plates

151.58 V

Explanation:

From the question,

The work done in a circuit in moving a charge is given as,

W = 1/2QV Equation 1

Where W = Work done in moving the charge, Q = The magnitude of charge, V = potential difference between the plates.

make V the subject of the equation

V = 2W/Q Equation 2

Given: W = 144 J. Q = 1.9 C

Substitute into equation 2

V = 2(144)/1.9

V = 151.58 V

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..