Data R1 = Resistance was 1009, Voltage was .56 and Current was .76
R2= Resistance wsa 1031, Voltage ws .49 and Current was 9.39
The equations in Pre-Lab Question 3 assumed the two top resistors were equal. Use the data collected to calculate the average of R1 and R2. This number will be used for the theoretical calculations. Show your work.

   R _average = 1020 Ω

Explanation:

In your exercise, two circuits were assembled and you wanted to test the ohm's law equations with them, for those you surely wanted the resistance to be equal, the variations of these resistances ( R= 1 KΩ) are within the tolerance range of them, which for good resistances is 5% which gives a fluctuation of 50 Ω.

If more exact calculations are desired, the average of the resistance value can be used, which is the sum of the values between the number of resistances

         R_average = 1 / n Σ

where R_{i} are the values of each resistance and n the number of resistances.

        R_average = (1009 + 1031) / 2

        R _average = 1020 Ω

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this