A ball is projected at an angle of elevation of 60 ° with an initial velocity of 120m/s. calculate 1) The time taken to get to the maximum height
ii) the time of flight

Explanation:

It is given that,

The angle of projection is 60 degrees

Initial velocity of the ball is 120 m/s

We need to find the time taken to get to the maximum height and the time of flight.

Time taken to reach the maximum height is given by :

g is acceleration due to gravity

(ii) Time of flight,

So,

Hence, this is the required solution.

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s

wavelength divides in half and speed stays the same.