The linear charge density on the inner conductor is and the linear charge density on the outer conductor is

Complete Question

The complete question is  shown on the first uploaded image (reference for Photobucket )

The  electric field is  

Explanation:

 From the question we are told that

    The linear charge density on the inner conductor is  

    The linear charge density on the outer conductor is

     The position of interest is r =  37.3 mm =0.0373 m

Now this position we are considering is within the outer conductor so the electric field  at this point is due to the inner conductor (This is because the charges on the conductor a taken to be on the surface of the conductor according to Gauss Law )

Generally according to Gauss Law

=>    

substituting values  

The  negative  sign tell us that the direction of the electric field is radially inwards

    =>  

iron would move it is magnetic there is a mag field around the current in the wire

more than, less

less than, more