.50-kg stone is dropped from rest at a height of 3.75 m. What impulse does gravity impart to this stone from the instant it is dropped until it hits the ground, assuming negligible air resistance

21.41 kg-m/s.

Explanation:

Data provided

Height = 3.75 m

Mass of stone = 2.50 kg

The computation of impulse is shown below:-

First we will compute the time using motion's equation  which is

as,

s indicates height

u indicates initial speed

t indicates time

Now, we will use the equation and put the values

t = 0.874 seconds

After computing the time now we will find put the impulse  which is

Now we will put the values into the above formula to reach the impulse

J = 21.41 kg-m/s.

powerful computers now, not then

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards