An eagle is flying above a mountain of height 2,700 m above sea level. Calculate the pressure on the eagle if the average density of air is 1.3 kg/m3,the atmospheric pressure at sea level is 76 cm Hg, and the density of mercury is 13,600 kg/m3.

The correct option is;

(A) 25.8 cmHg

Explanation:

The given parameters are;

The height of the mountain over which the eagle is flying = 2700 m

The average density of air, ρₐ = 1.3 kg/m³

The atmospheric pressure at sea level = 76 cmHg = 0.76 mHg

The density of mercury, = 13,600 kg/m³

The formula for pressure, p, is p = ρ·g·h

The pressure in the atmosphere = 13,600 × 0.76 × g = 10,336·g

The equivalent height of air is found as follows;

1.3 × g × h = 10,336·g

h = 10,336/1.3 = 7,950.769 meters

Therefore;

The pressure of the atmosphere at 2,700 meters, p₂₇₀₀ = (2,700/7,950.769) × 76 cm Hg

Which gives;

p₂₇₀₀ = 25.808 cmHg ≈ 25.8 cmHg.

the arctic is a region of the planet, north of the arctic circle, and includes the arctic ocean, greenland, baffin island, other smaller northern islands, and the far northern parts of europe, russia (siberia), alaska and canada.

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