A water pipe tapers down from an initial radius of R1 = 0.2 m to a final radius of R2 = 0.09 m. The water flows at a velocity v1 = 0.87 m/s in the larger section of pipe. What is the volume flow rate of the water?

0.109  m/s

Explanation:

The calculation of the volume flow rate of the water is shown below:-

Av = Velocity ()(Radius)^2

= 0.87()(0.2)^2

= 0.135258 m^3 / sec

= 0.109371429 m/s

or

= 0.109

So, for calculating the volume flow rate of the water we simply applied the above formula i.e by multiplying the velocity with pi and squaring of radius so that the volume could come

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6