You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 272 N in the negative x direction to try and move the 61 kg refrigerator. The coefficient of static friction is 0.62. (a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude (in N) and direction.

F_f = 370.636 N

Explanation:

We are given;

co-effficient of static friction;μ = 0.62

mass of the object;m = 61 kg

acceleration due to gravity;g = 9.8 m/s²

The maximum force of static friction is given by the formula:

F_f = μmg

Plugging in the relevant values, we have;

F_f = 0.62 × 61 × 9.8

F_f = 370.636 N

Now, we are told that a horizontal force of 272 N in the negative x direction to try and move.

Since the Frictional force exceeds this horizontal force, it means the Fridge is not going to move and would require a greater force

+15-35=-20

going in opposite directions

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j