A small truck has a mass of 2065 kg. How much work is required to decrease the speed of the vehicle from 23.0 m/s to 12.0 m/s on a level road

397.51 kJ

Explanation:

Since the change in velocity is done on a level road, there is no change in the potential energy. The workdone is the workdone on reducing the kinetic energy.

Workdone W = change in kinetic energy ∆K.E

W = ∆K.E

K.E = 0.5mv^2

∆K.E = 0.5m(m1^2 - m2^2)

Given;

Mass m = 2065 kg

Initial velocity v1 = 23.0 m/s

Final velocity v2 = 12.0 m/s

W = ∆K.E = 0.5m(m1^2 - m2^2)

Substituting the given values;

W = ∆K.E = 0.5×2065(23^2 - 12^2)

W = 397512.5J

W = 397.51 kJ

the inner core.

good luck: )

klicker