A baseball is launched horizontally from a height of 1.8 m. The baseball travels 0.5 m before hitting the ground. The velocity of the baseball, rounded to the nearest hundredth, is _ m/s.

The velocity of the baseball, rounded to the nearest hundredth, is 0.82 m/s.

Explanation:

We will use equation of motion:

h is the initial height

u = 0 = Initial vertical velocity

= Acceleration of gravity

t = Time

We are given that A baseball is launched horizontally from a height of 1.8 m.

So, Substitute h = 1.8 m

We are given that The baseball travels 0.5 m before hitting the ground.

Now Distance = 0.5 m

Time = 0.61 sec

To Find Speed

So, Speed = 0.82 m/s

Hence The velocity of the baseball, rounded to the nearest hundredth, is 0.82 m/s.