A d'Arsonal meter with an internal resistance of 1 kohm requires 10 mA to produce full-scale deflection. Calculate thew value of a series

A d’Arsonval meter with an internal resistance of 1 kΩ requires 10 mA to produce full-scale deflection. Calculate the value of a series resistance needed to measure 50 V of full scale.

4kΩ

Given;

internal resistance, r = 1kΩ

current, I = 10mA = 0.01A

Voltage of full scale, V = 50V

Since there is full scale voltage of 50V, then the combined or total resistance (R) of the circuit is given as follows;

From Ohm's law

V = IR

R =                 [substitute the values of V and I]

R =

R = 5000Ω = 5kΩ

The combined resistance (R) is actually the total resistance of the series arrangement of the series resistance() and the internal resistance (r) in the circuit. i.e

R = + r

= R - r                 [Substitute the values of R and r]

= 5kΩ - 1kΩ

= 4kΩ

Therefore the series resistance is 4kΩ

d

explanation:

i think the answer is d. but im not sure!

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c) both a and b.