what is the maximum torque on a coil 5 cm x 12 cm, composed of 600 turns, when it is carrying a current of 10^-5 A in a uniform field of .1 T

3.6×10⁻⁶  Nm

Explanation:

From the question,

The expression for maximum torque is given as

τ = BANIEquation 1

where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.

Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.

Substitute these values into equation 1

τ = 0.1(0.006)(600)(10⁻⁵)

τ = 3.6×10⁻⁶  Nm

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explanation: