What is the measure, in degrees, of the acute angle formed by the minute hand and the hour hand on a standard clock when it indicates $9$:$40$

9.666666º

Explanation:

In this exercise we must transform from hexadecimal units and decimal units.

For this we must take into account that in the sexagesimal system the base is 60 and in the decimal system the base is 10. This means that by taking 60 minutes we have a degree

 transform

               9º 40 ’a Aº

we use a direct proportion rule, where 60 minutes is equivalent to 10 decinal minutes

           40 ’[hexadecimals] = 40‘ (10/60) = 6,666 ’[decimals]

let's take these pleasant decimal minutes

          6.666 ’= 6.6666 (1/10) = 0.66666º

we already have all the units in degrees, we can add them

          9º + 0.666666º = 9.666666º

the answer is false

explanation:

vapour or gas assuming atmospheriv pressure