DOUBLE POINTS! A tuning fork of 500 Hz is struck in a room with a speed of sound of 340 m/s. What is the distance between a point of rarefaction and the next compression point, in the resulting sound?

Actually Welcome to the Concept of the Waves and it's motion.

So we here apply the formula as,

Velocity = frequency*wavelength

so here we get as,

340 = 500 * Lambda

Lambda = 340/500

so we get the distance as,

L = 0.68 m

λ = 0.68 m

Explanation:

Distance between a point of rarefaction and the next compression point is actually the wavelength (λ)

So, we'll find wavelength here:

Given:

Frequency = f = 500 Hz

Speed = v = 340 m/s

Required:

Wavelength = λ = ?

Formula:

v = f λ

Solution:

λ = v/f

λ = 340/500

λ = 0.68 m

this is a good question! i'll do some research and come back when i have the answer!