Una Fuerza F Aplicada a un objeto de masa m1 produce Una Aceleracion De 3.00m/s^2 La Misma Fuerza Aplicada a un segundo objeto de masa m2 Produce una Aceleracion De 1.00m/s^2a) Cual Es El Valor de la relacion m1/m2? B) Si m1 y m2 se combinan en un objeto ¿Cual Es Su Aceleracion Bajo La Accion De La Fuerza F?

(a)   m1/m2 = 1/3

(b)   a = 0.75m/s^2

Explanation:

You have the following relations:

For an object of mass m1:

      (1)

For an object of mass m2:

       (2)

(a) In order to calculate the quotient m1/m2 you use the fact that F1=F2=F.

You divide the equation (1) into the equation (2):

The quotient m1/m2 = 1/3

(b) For the case of a mass of m1+m2, you have:

        (3)

To find the values of the acceleration you divide the previous equation into the equation (2):

The new acceleratio for an object of mass m1+m2 is 3/4m/s^2 = 0.75m/s^2

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.