b. A string is wrapped around a pulley of radius 0.05 m and moment of inertia 0.2 kg  m2. If the string is pulled with a force F, the resulting angular acceleration of the pulley is 2 rad/s2. Determine the magnitude of the force F.

f = 8 N

Explanation:

Data provided in the question

Radius of the pulley  = r = 0.05 m

Moment of inertia = (I) = 0.2 kg.m^{2}

Angular acceleration = ∝ = 2 rad/sec

Based on the above information

As we know that

Torque is

And,

Torque is also

So,

We can say that

0.05f = 0.4

f = 8 N

We simply applied the above formulas

ill do it for 100, also this isnt 80 its 40

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge