For safety in climbing, a mountaineer uses a nylon rope that is 55 m long and 1.3 cm in diameter. When supporting a(n) 83-kg climber, the rope elongates 1.4 m. Find its Young's modulus.

The Young's modulus of the rope is .

Given data:

The length of rope is, L = 55 m.

The diameter of rope is, d = 1.3 cm = 0.013 m.

The mass of climber is, m = 83 kg.

The elongation of rope is, .

The ratio of stress and strain produced in a material is known as Young's Modulus of material . Then,

Here,

W is the weight of climber and its value is, W = mg.

A is the cross-sectional area of rope and its value is, .

Solving as,

Thus, we can conclude that the Young's modulus of the rope is .

Learn more about the Young's modulus here:

link

Young's modulus(Y) = 2.4 × 10⁸ (Approx)

Explanation:

Given:

Length of rope (l) = 55 m

Diameter of rope = 1.3 cm

Radius of rope (r) = 1.3 / 2 = 0.65 cm = 0.0065 m

Weight of climber (m) = 83 kg

Rope elongate(Δl) = 1.4 m

Find:

Young's modulus(Y).

Computation:

Force (F) = Weight of climber (m) × g

Force (F) = 83 × 9.8

Force (F) = 813.4 N

Area of rope (A) = πr²

Area of rope (A) = 0.000132665

Young's modulus(Y) =

Young's modulus(Y) = 44,737 / 0.000185731

Young's modulus(Y) = 2.4 × 10⁸ (Approx)

frequency or wavelenth of em radiation in a vacuum

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer