Two parallel plates having charges of equal magnitude but opposite sign are separated by 15.0 cm. Each plate has a surface charge density of 31.0 nC/m^2. A proton is released from rest at the positive plate. Required:a. Determine the magnitude of the electric field between the plates from the charge density. b. Determine the kinetic energy of the proton when it reaches the negative plate. c. Determine the speed of the proton just before it strikes the negative plate. d. Determine the acceleration of the proton. e. Determine the force on the proton. f. From the force, find the magnitude of the electric field. kN/C Show that it is equal to that electric field found from the charge densities on the plates.

nah.   i'm just sleepy.

d) physical means can be used to separate the components of air.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

the journeys of marquette, joliet and la salle a) new france expand.

all three of these explorers explored the midwest and the area around the great lakes, which they subsequently claimed for france.

this was a big portion of territory and expanded new france which before then only consisted of quebec province in northeastern canada