An apple dropped from the branch of a tree hits the ground in 0.5 s. If the acceleration of the apple during its motion is 10 ms-2 in the downward direction. Calculate Its speed just before it hits the ground. What is its average velocity during 0.5 s? Calculate the height of the branch of the tree from the ground?

Given that,

Time = 0.5 s

Acceleration = 10 m/s²

(I). We need to calculate the speed of apple

Using equation of motion

Where, v = speed

u = initial speed

a = acceleration

t = time

Put the value into the formula

(III). We need to calculate the height of the branch of the tree from the ground

Using equation of motion

Put the value into the formula

(II). We need to calculate the average velocity during 0.5 sec

Using formula of average velocity

Where, = final position

= initial position

Put the value into the formula

Hence, (I). The speed of apple is 5 m/s.

(II). The average velocity during 0.5 sec is 2.5 m/s

(III). The height of the branch of the tree from the ground is 1.25 m.

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