A steel wire with mass 25.3 g and length 1.62 m is strung on a bass so that the distance from the nut to the bridge is 1.10 m. (a) Compute the linear density of the string. kg/m (b) What velocity wave on the string will produce the desired fundamental frequency of the E1 string, 41.2 Hz

(a)    μ = 0.015kg/m

(b)    v = 90.64m/s

Explanation:

(a) The linear density of the string is given by the following relation:

          (1)

m: mass of the string = 25.3g = 25.3*10-3 kg

L: length of the string = 1.62m

The linear density of the string is 0.015kg/m

(b) The velocity of the string for the fundamental frequency is:

        (2)

f1: fundamental frequency = 41.2 Hz

vs: speed of the wave

l: distance between the fixed extremes of the string = 1.10m

You solve for v in the equation (2) and replace the values of the other parameters:

The speed of the wave for the fundamental frequency is 90.64m/s

divide the right side by the left side

0.024÷1.2=0.02 for example

cell differentiation  is how generic embryonic  cells  become specialized  cells. this occurs  through a process called gene expression. gene expression is the specific combination of genes that are turned on or off (expressed or repressed), and this is what dictates how a  cell  functions.

explanation: