A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent driver leaves the car in neutral, and the emergency brakes are defective. The car rolls from rest down the incline with a constant acceleration of 3.82 m/s2 for a distance of 60.0 m to the edge of the cliff, which is 50.0 m above the ocean. Required:
Find the car’s position relative to the base of the cliff when the car lands in the ocean.

The position is   relative to the base of the ocean

Explanation:

From the question we are told that

    The angle made by the incline with the horizontal is

    The constant acceleration is

    The distance covered is

    The height of the cliff is

The velocity of the car is mathematically represented as

The initial velocity of the car is  u= 0

So

substituting values

The vertical component of this velocity is

substituting values

The negative sign is because is moving in the negative direction of the y-axis

The horizontal  component of this velocity is

Now according to equation of motion we have

substituting  values

using quadratic equation we have that

given that time cannot be negative

The  car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as

substituting values

e/c, where e is its total energy

it's a b and