A body moving with uniform acceleration has two points (5,15) and (20,60) on the (v t) graphs of its motion. calculate the acceleration

3m/s²

Explanation:

The slope on a velocity time graph represents the acceleration, so if you simply use the slope formula, you can find the acceleration between those two points.

m=rise/run

m=(60-15)/(20-5)

m=45/15

m=3 m/s ² squared (therefore this is your constant acceleration from those two points).

(75°f − 32) × 5/9 = 23.889°c