You pull a force of 255 N on a piece of luggage of mass 68 kg but does not move the coefficient of friction between the luggage in the floor is .7 what is the force of static friction acting on the luggage

255N

Explanation:

Given the following :

Applied force (F) = 255N

Mass (M) of the body = 68kg

Coefficient of static friction (Us) = 0.7

Recall:

Us = frictional force / normal reaction(N)

Normal reaction( N) = mass × acceleration due to gravity

N = mg = 68 × 9.8m/s^2 = 666.4N

Therefore,

Frictional force = coefficient of static friction × normal reaction

Frictional force = 0.7 × 666.4 = 466.5N.

In other for the body to move, the minimum applied force must be greater than the frictional force in other to overcome the force of friction.

Here, the force applied on the object is equal to the force of static friction which is less than the frictional force.

255N = force of static friction.

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5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000