Which shows the correct lens equation? The inverse of f equals the inverse of d Subscript o Baseline times the inverse of d Subscript I Baseline. The inverse of f equals StartFraction d Subscript o over d Subscript I Baseline EndFraction plus StartFraction d Subscript I Baseline over d Subscript o Baseline EndFraction. The inverse of f equals the inverse of d Subscript o Baseline minus the inverse of d Subscript I Baseline. The inverse of f equals the inverse of d Subscript o Baseline plus the inverse of d Subscript I Baseline.